Question

If ab=5, a-b=4. Then find the value of (a^3+b^3).

Answer 1

(a-b)^2=a^2+b^2-2ab

a^2+b^2=26

(a+b)^2-2ab=a^2+b^2

(a+b)^2=36

a+b=6

a^3+b^3=(a+b) (a^2+b^2-ab)

a^3+b^3=6*(26-5)

a^3+b^3=126

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