If ab=5 and a^2+b^2=9
Find the value of 3(a+b)^2 - 2(a-b)^2
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^2=square
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Answer:
3(a+b)^2 - 2(a-b)^2
=>3(a^2+b^2+2ab) –2(a^2+b^2–2ab)
=>3(9+10) –2(9–10)
=>3(19) –2(–1)
=> 57–(–2)
=>57+2=59
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