Math, asked by Akash1321, 1 year ago

if ab=5 and a-b=2,find the value of a3-b3

Answers

Answered by wifilethbridge
39

Answer:

38

Step-by-step explanation:

Given : ab=5

            a-b=2

To Find : a^3-b^3

Solution :

Formula :(a-b)^{3} =a^3-b^3-3ab(a-b)

Substitute the given values

(2)^{3} =a^3-b^3-(3*5)(2)

8=a^3-b^3-(15)(2)

8=a^3-b^3-30

8+30=a^3-b^3

38=a^3-b^3

Hence the value of a^3-b^3 is 38

Answered by elixirplayz5
10

Answer:

Answer:

38

Step-by-step explanation:

Given : ab=5

           a-b=2

To Find : a^3-b^3

Solution :

Formula :(a-b)^{3} =a^3-b^3-3ab(a-b)

Substitute the given values

(2)^{3} =a^3-b^3-(3*5)(2)

8=a^3-b^3-(15)(2)

8=a^3-b^3-30

8+30=a^3-b^3

38=a^3-b^3

Hence the value of a^3-b^3 is 38

Step-by-step explanation:

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