If AB = 5 cm, BC = 12 cm and AB is perpendicular to BC, then fi nd the radius of the circle passing throughthe points A, B and C.
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Given- A,B & C are points such that AB=12cm and BC=16cm and BC⊥AB.
To find out- the radius of the circle passing through A,B & C=?
Solution- BC⊥AB i.e ∠ABC=90
0
and ΔABC is a right one with AC as hypotenuse. ∴AC=
AB
2
+BC
2
=
12
2
+16
2
cm=20cm. So the circle passing through A,B & C will have its diameter as AC.
∴ Its radius=
2
1
×20cm=10cm
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