if ab = 6,bc = 8 and ac = 13,fimd the value of a^2+b^2+c^2
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1
Answer:
98
Step-by-step explanation:
ab=6 so lets assume a=3 b=3
bc=8 b = 3 so c = 8-3 =5
ac=13 c = 5 so a = 13-5 = 8
so a = 8 b = 3 c = 5
a^2 + b^2 + c^2 = 8^2 + 3^2 + 5^2
= 64+9+25=98
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