Question

if AB +7c =102,where a,b,c is not equal to 0
,then a +b+c=​

Answer 1

Answer:

Here a+b+c=14

Step-by-step explanation:

From the given number, B+C is either 2 or the two digit number that gives the unit digit as 2.

It is given that B ≠ 0, C ≠ 0,

If B or C = 5 or 7, then A should be 3, then it becomes A+B+C = 14

Or else, if B= C = 6, and A = 2, we will get A+B+C = 14

Answer 2

Answer:

ab+7c=102

let 7c=7×10

102-70=32

32=8×4

so 8×4+7×10=102

a+b+c=8+4+10

=22