Question

If AB=8cm,BC=9cm,Ac=6cm

And AD in the bisector of A.Find

a)BD:CD

b)What is the ratio of the area of ∆ABD and ∆ACD.​

Answer 1

Answer:

ANSWER

Using Pythagoras theorem, In a Rightangled triangle AOC we have

AO

2

+OC

2

=AC

2

⇒y

2

+x

2

=3

2

∴y

2

=9−x

2

.......(1)

Using Pythagoras theorem, In a Rightangled triangle AOB we have

AO

2

+OB

2

=AB

2

⇒y

2

+(x+6)

2

=8

2

⇒9−x

2

+x

2

+12x+36=64

⇒12x+45=64

⇒12x=64−45=19

⇒x=

12

19

=1.58cm

Hence OC=1.58cm