if AB×AB=ACB solve the cryptarithm
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Given:
AB×AB=ACB
To Solve:
The cryptarithm.
Solution:
- AB represent a 2 digit number with A at 10s place and B at units place.
We are multiplying AB with AB.
- A and B can take any values from 0 to 9.
But If We multiply B by B to get B itself at the units place of the product,
- B can be 0 , 1 , 5, 6 .
- Also A should be at the 10s place , therefore middle term should not have any carry over.
- Middle term is AB + AB = C
- Therefore B cannot be 5 or 6 .
- Also A cannot be 5 or 6.
- Therefore A and B can be 0 or 1
If we assume B and C to be different numbers , B cannot be 0 , as this makes C also 0.
- Therefore, B = 1
- Then A also 1
- C = AB + BA = 2
Therefore AB = 11, AB×AB=ACB and ACB = 121
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