if AB=AC and BD=DC ,then angle ADB is
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Angle ADB = 90 degrees
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☛︎ AB = AC
☛︎ BD = DC
Angle ADB = ?
In ∆ADB and ∆ADC
- AB = AC (Given)
- BD = DC (Given)
- AD Common
Therefore, ∆ ADB ~= ∆ ADC ...[By S-S-S property]
Angle ADB + Angle ADC = 180°
Angle ADB = Angle ADC = 90°
Therefore, angle ADB = 90°
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