Question

If AB, AC and PQ are the tangents of a circle with centre O. prove that perimeter of APQ=2AB.​

Answer 1

Hence it is proved that, the perimeter of APQ=2AB.​

Given,

AB, AC and PQ are the tangents of a circle with centre O

As we know that, the tangents drawn from the same external point are equal in length.

⇒ AB = AC

Similarly, we have,

PQ = PB + QC

Perimeter of APQ  = AP + PQ + AQ

= AP + (PB + QC) + AQ

= (AP + PB) + (QC + AQ)

= AB + AC

= AB + AB

= 2 AB

∴ Perimeter of APQ = 2 AB

Answer 2

Step-by-step explanation:

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