If AB = AC, BC side of triangle ABC is extended to E and if
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I think the question is half so please do write full question, so that I can help you .
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AB=AC(isoscelestriangleABC)→(i)
EC=BD(given)
⇒EB+BC=BC+CD
⇒EB=CD→(ii)
∠ABC=∠ACB(isoscelestriangleABC)
180−∠ABC=180=∠ACB
⇒∠ABE=ACD→(iii)
fromequation(i),(ii),(iii)
ΔABE≅ΔACD
byCPCT
AE=ADhenceproved.
it was very hard writing this whole answer by typing ..pls mark as brainliest
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