Question

if AB=AC+BC, then what do you conclude about the points A B C​

Answer 1

Answer:

Let ∣A∣=0

∴A−1 exists.

Given AB=AC

Now, pre multiplying by A−1 on both sides. we get,

A−1AB=A−1AC

⇒IB=IC

⇒B=C

So, A is non singular.

Option B is correct.