if AB=AC. P and Q are on side AB and AC such that AP= AQ .Prove that CP=BQ.
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As in triangle abc ab=ac it is a isosceles triangle and angle abc=angle acb
AB=AC
AP+PB=AQ+QC
AS AP=AQ
PB=QC
IN TRIANGLE PBC AND TRIANGLE QCB
PB=QC(PROVED)
ANGLE ABC=ANGLE ACB (PROVED)
BC=CB(COMMON SIDE)
BY SAS CONGRUENCY TRIANGLE PBC≅ TRIANGLE QCB
BY CPCT: CP = BQ
HENCE PROVED
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