If AB,AC,PQ are tangents in fig.8.56 and AB=5 cm then find the perimeter of triangle APQ
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Tangents from an external point to a circle are equal so
PX=PB and QX=QC
AB=BC=5cm
So,
AP+PB=AQ+QC
AP+PX=AQ+QX=5cm
perimeter of triangle = 10 cm
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