Question

if AB , AC , PQ are tangents in Fig. and AB = 5 cm, find the perimeter of ∆APQ. ​

Answer 1

$\huge\mathfrak\red{☟ \: \: \: answer \: \: \: \: ✎}$

Let PQ touch the circle at point R. We know that,tangents drawn from a external point to a circle are equal in length.

$: \: AB = AC = 5 cm$

$⇒AP + BP = AQ + QC =cm$

$⇒AP + PR = AQ + QR =cm$

$[BP = PR \: and \: QC = QR]$

$now \: perimeter \: of \: ∆APQ=$

$Addition \: of \: all \: three \: sides \\ = AP + PQ + AQ$

$= AP + RP + QR + AQ$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [ \: from \: (i)]$

$= 5 + 5$

$= 10 \: cm$

$The \: Perimeter\: of \:∆APQ \: is \:10cm$

$\\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$