If
AB & CD are
two chords of the
circle
intersecting each other at
right angle
at P and if R is
centre of circle then prove
that
PA + PB + PC +
PD = 2 PR
the
(by vectors)
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Step-by-step explanation:
CAO = ∠ODB = x [angles in same segment ] ---- (i)
Now, in right angled ΔDOB ,
∠ODB + ∠DOB + ∠OBD = 180°
⇒ x + 90° + y =180° (using equation i)
⇒ x + y = 90°
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2
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