Question

If AB and CD are two chords of a circle intersecting at point E, as per the given figure. Thenhelppp

Answer 1

Answer:

angle BEQ = Angle CEQ

Step-by-step explanation:

triangle MOE is congruent to Triangle NOE by RHS( chord AB and CD should be equal)

by CPCT:

angle MEO( BEQ) = angle NEO( CEQ)

Answer 2

Answer:

Therefore, the correct answer is option (b) $\angle B E Q=\angle C E Q$.

Step-by-step explanation:

Given:

Let $A B$ and $CD$ are two chords of a circle intersecting at $E$.

Step 1

We know that the center of the chord is equal in length.

$\Rightarrow O M=O N$

In $\Delta_{s}$ $OEM$ and $OEN$

$O M=O N$ [chord from center $O$ ]

$O E=O E$ [Common]

$\angle O M E=\angle O N E=90^{\circ} \quadr$

Step 2

Therefore,

$\triangle O E M \sim \triangle O E N$ [SAS congruency]

$\Rightarrow \angle B E Q=\angle C E Q$ [CPCT]

Therefore, the correct answer is option (b) $\angle B E Q=\angle C E Q$.

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