If AB and CD are two chords of a circle which when produced meet at a point P and if PA=PC,show that AB=CD
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Step-by-step explanation:
Given: AB and CD are two chords of a circle intersecting at P
AP = CP
To prove : AB = CD
PA PB = PC PD
PB = PD (as PA = PC)
Now, AB = PA - PB = PC - PD = CD
AB = CD
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