If AB and CD intersects each other at point O. angle AOD = 4x+20 and angle COB = 3y+ 15 and given x:y = 2:3. find angle AOC. pls urgent!!!!
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Answer:
X = 37
∠bod = 37°
∠aod = 143°
∠aoc = 37°
∠boc = 143°
Step-by-step explanation:
ab is a straight line
=> ∠aod + ∠bod = 180°
∠bod = X°
∠aod = (4X - 5) °
=> X° + (4X - 5) ° = 180°
=> 5X° = 185°
=> X = 37
∠bod = 37°
∠aod = 4X - 5 = 4*37 - 5 = 143°
∠aoc = ∠bod (opposite angles)
=> ∠aoc = 37°
∠boc = ∠aod (opposite angles)
=> ∠boc = 143°
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