If AB and MN bisect each othet at O and AM and BN are perpendicular on XY , prove that triangles OAM and OBN aee congruent and hence prove that AM=BN
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AB and MN bisect each other
therefore AO=BO,MO=NO
in TriangleAMO and BNO
angle AMO=angleBNO
AO=BO
MO=NO
by RHS congruence rule
triangleAMO and BNO are congruent
therefore triangleOAM andOBN are also congruent
and hence AM=BN
therefore AO=BO,MO=NO
in TriangleAMO and BNO
angle AMO=angleBNO
AO=BO
MO=NO
by RHS congruence rule
triangleAMO and BNO are congruent
therefore triangleOAM andOBN are also congruent
and hence AM=BN
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