Question

if ab-b+1=0 and bc-c+1=0,then find the value of (a-ac)​

Answer 1

a form first eq | C form second eq

ab-b+1=0 | bc-c+1=0

a=b-1/b | -c=-(bc+1)

| c=bc+1

put in a-ac

( b-1)/b- (b-1)/b ( bc+1)

(b-1)/b- (b2c+b-bc-1)/b

(b-1-b2c-b+bc+1)/b

(b-b+1-1-b2c+bc)/b

(-b2c+bc)/b

b(-bc+c)/b

-bc+c

c(-b+1)