if ab-b+1=0 and bc-c+1=0,then find the value of (a-ac)
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We have,ab−b+1=0 ...(1)bc−c+1=0 ...(2)From eq(2) , we haveb=c−1cput this value in eq(1), we geta(c−1c)−c−1c+1=0⇒ac−a−c+1+cc=0⇒ac−a+1=0
thalif123:
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