Math, asked by surekhakharade3, 5 months ago


If AB :BC = 3:5 then how many equal parts seg AC
divided to get point B​

Answers

Answered by sharvanikulkarni
3

Step-by-step explanation:

the answer is .....

8 parts

Answered by jaseenanoufal2022sl
1

Answer:

The line segment AC is divided into 8 equal parts  and AB is of 3 equal parts.

Step-by-step explanation:

Given: AB:BC = 3:5, line segment AC.

To find: the number of equal parts seg AC  divided to get point B.

Solution: AB:BC =3:5

Total parts = 3+5 = 8

AB =3x and BC =5x.

∴    The line segment AC is divided into 8 equal parts to get the point B and AB is of 3 equal parts.

#SPJ2      

Similar questions