Question

If ab=bc=a units and ac = root 2 are the sides of triangle abc then measure of angle b is? Please ans thank you

Answer 1

Clearly ABC is an isosceles triangle.  AB = BC = a.
AC = √2

Draw a perpendicular from B onto AC to meet AC at D.  Clearly, AD = CD.
Also the measure of ∠ABD = measure ∠CBD = 1/2 * measure ∠B

Now in the triangle ABD, we have Sin (ABD) = (√2/2)  / a

so measure ∠B = 2 * Sin⁻¹ [1/√2a ]

Answer 2

Answer:

∠B = 2 * Sin⁻¹ [1/√2a ]

Step-by-step explanation:

ABC is clearly an isosceles triangle. AC = 2 AB = BC = 

Draw a perpendicular from B to AC, intersecting AC at D. Obviously, AD = CD.

Furthermore, the measure of ABD = measure CBD = 1/2 * measure B

We now have Sin (ABD) = (2/2) / an in the triangle ABD.

As a result, measure B = 2 * Sin1 [1/2a].

The symbol " represents perpendicular lines. If m and n are two lines that intersect at 90°, they are perpendicular to each other and are represented as m n. The intersection of two perpendicular lines is known as the foot of the perpendicular.

Perpendicular Line Properties

• These lines are always at right angles when they intersect.
• If two lines are perpendicular to each other, they are parallel and will never intersect.

For similar questions refer-https://brainly.in/question/37061613

#SPJ2