If AB=BC=AC , then prove that angle A=angle B= angle C
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Step-by-step explanation:
Let, the angle of side AB = x
(if the side of the triangle is equal then it's the angle is also the same)
According to the question, AB=BC=AC
therefore, x= angle of BC= angle of AC
Now,
x+x+x =180°
3x= 180°
x=180°/3
x= 60°
therefore, angle A= 60° = angle B= angle C
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