If AB, BC and CD are equal chords of a circle with O as a centre and AD diameter, than ∠AOB =
A. 60°
B. 90°
C. 120°
D. None of these
Answers
Answered by
0
Answer:
option B is the correct answer
Answered by
1
Answer:
As we know that equal chords make equal angle at the centre.
Therefore,
∠AOB=∠BOC=∠COD
∠AOB+∠BOC+∠COD=180°[ Linear pair ]
⇒3∠AOB=180°
⇒∠AOB=60°
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