Math, asked by starboyk1923, 8 months ago

If AB, BC and CD are equal chords of a circle with O as a centre and AD diameter, than ∠AOB =
A. 60°
B. 90°
C. 120°
D. None of these

Answers

Answered by borsurerajgmailcom
0

Answer:

option B is the correct answer

Answered by seabird1234
1

Answer:

As we know that equal chords make equal angle at the centre.

Therefore,

∠AOB=∠BOC=∠COD

∠AOB+∠BOC+∠COD=180°[ Linear pair ]

⇒3∠AOB=180°

⇒∠AOB=60°

Attachments:
Similar questions