Math, asked by viji18net, 1 year ago

If, AB⊥BC and DE⊥ AC. Prove that ΔABC~ΔAED

Answers

Answered by Anonymous
2

Answer:

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by S.A.S congruency it can be proved

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Answered by vbhai97979
1

Answer:

SOLUTION :

Given : ΔACB is right angled triangle at C = 90°.

From the figure : BC = 12 cm , AD=3 cm, DC = 2 cm.

AC = AD + DC = 3 +2= 5 cm

In ∆ACB,

AB² = AC² + BC² (by pythagoras theorem)

AB² = 5² + 12²

AB² = 25 + 144 = 169

AB= √169 = 13

AB = 13 cm

In ΔABC & ΔADE

∠BAC = ∠DAE (common)

∠ACB = ∠AED (each 90°)

ΔABC∼ΔADE (by A-A similarity criterion),

AB/AD = BC/DE = AC/AE

[Since corresponding sides of two similar triangles are proportional]

13/3 = 12/ DE = 5/AE

13/3 = 12/DE

13 DE = 12×3

DE = 36/13

13/3 = 5/AE

13 AE = 5×3

AE = 15/13

Hence, the length of DE= 36/13 & AE = 15/13

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