Question

if ab=BC andtriangle boc =55

Answer 1

you shoul first prrof al sides of tiangle equal an then make then by aas congruent rule.

and by using angle sum property

pic out all angles of triangle. Sol:

Here BO, CO are the angle bisectors of ∠PBC & ∠QCB intersect each othe at O.

∴ ∠1 = ∠2  and ∠3 = ∠4

Side AB and AC of ΔABC are produced to P and Q respectively.

∴ Exterior of ∠PBC = ∠A + ∠C --------------(1)

And Exterior of ∠QCB = ∠A + ∠B --------------(2)

Addiing (1) and (2) we get

∠PBC + ∠QCB = 2 ∠A + ∠B + ∠C.

2∠2 + 2∠3 = ∠A + 180°

∠2 + ∠3 = (1 /2)∠A + 90°  ----------(3)

But in a ΔBOC = ∠2 + ∠3 + ∠BOC = 180° --------( 4)

From equ (3) and (4) we get

(1 /2)∠A + 90° + ∠BOC = 180°

∠BOC = 90° - (1 /2)∠A

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Answer 2

by using aas property