Question

If ab+bc+ca=0, then find ((1/a²-bc)+(1/b²-ac)+(1/c²-ab))​.

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Answer 1

Answer:

0

Step-by-step explanation:

We need to substitute the value of - bc as ab + ac

So the first term simplies to

1/(a^2 + ab +ac)

which can further be simplified as

1/(a(a+b+c)

Similarly the other terms can be simplified as 1/(b(a+b+c) and 1/(c(a+b+c)

On taking lcm and adding the numerators

We get

(ab+bc+ca)/abc(a+b+c)

We know that Numerator is 0

So answer is 0