If ab+bc+ca=0 then find the value of 1/a2-bc/b2-ca/c2-ab
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Answer:
ab+bc+ca=0.,,,,
1/a²-bc/b²-ca/c²-ab this we have to find the value,,so .
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
- =a²+b²+c²+2(ab+bc+ca)
- =a²+b²+c²+2×0
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