Question

If ab+bc+ca = 0, then the value of (1/a^2-bc) + (1/b^2-ca) + (1/c^2 -ab) will be
(a) -1
(b) a+b+c
(c) abc
(d) 0​

Answer 1

Answer:

correct aption is - (B)

Step-by-step explanation:

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