If ab + bc+ ca = 10 and a^2 +b^2 +c^2 = 44 find a^3 +b^3 +c^3 -3abc.
Answers
Answered by
2
Answer:
(a+b+c)³=(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)−abc]
(a+b+c)³ = (a³+b³+c³) + 3(10)(a+b+c) -3abc
(a³+b³+c³) - 3abc = (a+b+c)³ - 30(a+b+c)
(a³+b³+c³) - 3abc = (a+b+c) [ (a+b+c)^2 - 30 ]
(a³+b³+c³) - 3abc = (a+b+c) [ 44 +10 -30 ]
I can do it only till here. Sorry.
plz follow me
Step-by-step explanation:
Similar questions