Math, asked by Kakurana007, 11 months ago

If ab+bc+ca=10and a^2+b^2+c^2=44 find a^3+b^3+c^3-3abc

Answers

Answered by vishalkumar5120
12

Answer:

The answer of this question is 272.

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Answered by yashasvipatwal
5

Answer:

(a+b+c)³=(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)−abc]

(a+b+c)³ = (a³+b³+c³) + 3(10)(a+b+c) -3abc

(a³+b³+c³) - 3abc = (a+b+c)³ - 30(a+b+c)

(a³+b³+c³) - 3abc = (a+b+c) [ (a+b+c)^2 - 30 ]

(a³+b³+c³) - 3abc = (a+b+c) [ 44 +10 -30 ]

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