Question

If ab+bc+ca=20 and a+b+c=11, find a2+b2+c2
guys pls answer exam now pls help

Answer 1

Given:-

ab+bc+ac=20 (Eq.1)

a+b+c=11 (Eq.2)

To Find:-

• a²+b²+c²

Solution:-

If

a+b+c=11

Squaring Both sides

that is

(a+b+c)²=11²

a²+b²+c²+2ab+2bc+2ac=121

a²+b²+c²+2(ab+bc+ac)=121

We know

From (Eq.1)

ab+bc+ca=20

a²+b²+c²+2(20)=121

a²+b²+c²+40=121

a²b²+c²=121-40

a²+b²+c²=81

Therefore the answer is 81

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