Question

If ab + bc + ca= 26, a+b+c=9 find a^2+b^2c^2

Answer 1

ANSWER:

ab + bc + ca = 26

a + b + c = 9

(SOBS)

(a + b + c)² = 9²

=> a² + b² + c² + 2(ab + bc + ca) = 81

=> a² + b² + c² = 81 - 2(26)

=> a² + b² + c² = 29

Answer 2

Answer:

a²+b²+c² = 29

Step-by-step explanation:

Given,

ab+bc+ca=26 and

a+b+c=9

(a+b+c)² = a²+b²+c² + 2 (ab+bc+ca)

9² = a²+b²+c² + 2(26)

81 = a²+b²+c² + 52

Therefore,

a²+b²+c² = 81 - 52

a²+b²+c² = 29