If ab+bc+ca =26 and a+b+c =9, find a^2 +b^2+c^2
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0
Step-by-step explanation:
6qwd684d65477d6587sdddff ( means I don't know)
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1
Answer:
29.
Step-by-step explanation:
Given, a+b+c=9 and ab+bc+ca=26.
We know, (a+b+c)^2 = a^2 + b^2 + c^2 + 2ab +2bc + 2ca
= (a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+bc+ca)
Putting the values here, we get,
(9)^2 = a^2 + b^2 + c^2 + 2(26)
81 = a^2 + b^2 + c^2 + 52
Thus a^2 + b^2 + c^2 = 81 - 52 i.e. 29.
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