if AB + BC is equals to 15 CM BC + CA is equals to 10 cm and AB+AC is equals to 13 cm then the perimeter of angle abc is
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Answered by
3
Answer:
AB + BC = 10 cm …(1)
BC + CA = 12 cm …(2)
CA + AB = 16 cm …(3)
Add (1), (2) and (3) to get
2AB + 2BC + 2CA = 10 + 12 + 16 = 38, or
Hence the perimeter of ABC = AB + BC + CA = 19 cm.
Answered by
1
Answer:
AB+BC = 10 cm
BC+CA = 12 cm
CA +AB = 16 cm
Adding we get 2AB + 2BC+2CA = 38 cm
AB+BC+CA = 19 cm
Hence the perimeter of the triangle is 19 cm
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