If AB || CD and AB = CD, prove that
AAOB = ADOC, OA = OD and OB = OC
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AB∥CD ( given )
In △AOB and △DOC,
∠AOB=∠DOC (Vertically opposite angles)
∠OAB=∠ODC (Alternate angles)
∠ABO=∠DCO (Alternate angles)
From AAA (angle-angle-angle) similarity theorem,
△AOB∼△DOC
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