If AB || CD and CD || EF, find angle ACE.
Please explain step by step.
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As per the diagram, lines CD∣∣EF and CE is transveral.
We know that sum of interior angles is equal to 180
o
∠ECD+∠CEF=180
o
∠ECD+130
o
=180
o
∠ECD=180−130
o
∠ECD=50
o
As per the diagram, lines AB∣∣CD and CA is transveral.
We know that alternate angles are equal.
∠BAC=∠ACD
∠BAC=∠ACE+∠ECD
70
o
=∠ACE+50
o
20
o
=∠ACE
∴∠ACE=20
o
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