Question

if AB//CD and EF//DQ then find the values of angle PDQ, AED DEF​

Answer 1

Angle CDP = angle AED ( Corresponding angle)

SO angle AED = 34 -(i)

Now,

Angle AED + Angle DEF + Angle FEB = 180 ( angles on straight line )

34 + Angle DEF + 78 = 180 ( Angle AED = 34 is proved above & Angle FEB = 78 given)

Angle DEF + 112 = 180

Angle DEF = 180-112

Angle DEF = 68

So Angle DEF = 68

Angle DEF = Angle PDQ ( Corresponding angle)

So Angle PDQ = 68

Answer 2

Step-by-step explanation:

By this way you can solve the problem