if AB//CD, angle APQ=50 and angle PRD=127 then find x,y
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Hello mate ☺
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Solution:
AB∥CD, ∠APQ=50° and ∠PRD=127° (Given)
∠x=50°=∠APQ (Alternate Interior Angles)
∠APR=∠PRD (Alternate Interior angles)
⇒50°+∠y=127°
⇒∠y=127°−50°=77°
Therefore, ∠x=50° and ∠y=77°
I hope, this will help you.☺
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Answer:
Use property of Alternate interior angles
∠APR = ∠PRD
50° + y = 127°
y = 127° − 50°
y = 77°
use same property of Alternate interior angles
∠APQ = ∠PQR
50° = x
∠ x = 50° and y = 77°
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