Question

If AB||CD , CD||EF and x : y = 3 : 2 find the value of z.

Answer 1

given x:y=3:2
AB//CD//EF
so x and y are co interior angles
i.e. x+y=180
3z+2z=180 (given 3:2)
5z=180
z=180÷5=36

so x=3×36=108 and 2×36=72.
Now x=z (alternate interior angles)
108 degree(ans)



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Answer 2

AB II EF
X+Y = 180 degree [Co-Interior Angle]
3a+2a = 180
5a = 180
a = 36 degree
X = 3a [Given ]
Z  = X 
Z = 108 degree