Question

If AB = DC, then AOB= DOC?

Answer 1

Let  buddy  , 

ABCD is a Δ in which 

1) AB║CD 

2) AB=2CD ..............................(given) 

In Δ AOB and COD

∠DOC  = ∠BOA  [ vertically opposite angle via (V.O.A property ) 

∠COD  = ∠ABO  [alternate interior angle property ] 

hence , 

∠DOC = ∠BOA 

now we can say that ΔAOB ≈ΔCOD

now using the similarity concept we can conclude the ratio of the areas of the 

similar triangle  is equal to the ratio of the square of their corrosponding sides  

area of triangle (AOB) : area of triangle COD =AB^2:CD^2

: area of triangle  COD)=(2CD)^2:CD^2

area of triangle ( AOB) : area of triangle ( COD)=4CD^2:CD^2

area of triangle AOB  : area of triangle  (COD) = 4 : 1.

HOPE THIS HELPS YOU BUDDY !

CHEERS ^_^  

Answer 2

i think u would have a diagram for this question?

so please attach it