Question

if AB||DE ,<BAC=35°&<CDE=53°,find<DCE&<DEC. and angles ke sahat

Answer 1

Hello mate ☺

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Solution:

It is given that AB∥DE. Therefore, ∠BAC=∠DEC              (Alternate Interior Angles)

∠BAC=35°      (Given)

Therefore, ∠DEC=35°

In ∆DCE, we have

∠DEC+∠CDE+∠DCE=180°         (Sum of three angles of a triangle =180°)

⇒35°+53°+∠DCE=180°

⇒∠DCE=180°−35°−53°=92°

I hope, this will help you.☺

Thank you______❤

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Answer 2

Answer:

∠DCE = 92

Step-by-step explanation:

In the question it is given

AB∥DE.

This implies ∠BAC=∠DEC          

   (Alternate Interior Angles)

∠BAC=35°      (Given)

Therefore from above

∠DEC=35°

Now, In ∆DCE,

Sum of three angles of a triangle = 180°

∠DEC+∠CDE+∠DCE=180°   

⇒35°+53°+∠DCE=180°

⇒∠DCE + 88 = 180°

= ∠DCE = 180-88

= 92

Hence, ∠DCE = 92