Question

If AB II CD, EF ⊥ CD and ∠GED = 1260, find ∠AGE, ∠GEF and ∠FGE. In Fig. 6.30.

Answer 1

AB || CD itersected by GE , therefore <AGE = <GED = 126^0 (pair of alt. int. angles)
<GED=<GEF+<FED
=<GEF + 90^0
, therefore <GEF = <GED-<FED
=126^0 - 90^0. =36^0
<FGE+<AGE = 180^0(linear pair)
126^0 +<FGE = 180^0
therefore, <FGE=54^0

Answer 2

ANSWER :-

AB||CD, EF ⊥ CD & <GE = 126°

★Find

<AGE, <GEF & <FGE

126 - 90

• 36

<GEF =36°

<AEF = 126° ( Alternate angle )

<GEF = 180 - 126 54° 180 ( Linear Pair)