if AB II EF, DE II BC, AC II DF, find x and y.
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GIVEN AB //DF AND DE is transversal
y =180-110= 70( co interior angles)
AB||EF AND AC IS TRANSVERSAL
X= 180-70=110 ( co interior angles)
y =180-110= 70( co interior angles)
AB||EF AND AC IS TRANSVERSAL
X= 180-70=110 ( co interior angles)
agrita29:
value of y is wrong. its 120 ...
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28
Let, Point P be the intersection of AB and DE.
=> ∠APD = 110 degrees Vertically Opposite angles
=> ∠DMB = ∠AME = 70 Degrees
Let, Q be the intersection of AB and DF
In Triangle DPQ,
∠DQP = 180 Degrees - 60 Degrees - 70 Degrees
∠DQP = 50 degrees
=> DFE = 50 Degrees (Interior angles as AB parallel to EF
Similarly you can compute remaining angles.
You will get
x = 120 degrees and y = 120 degrees
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