If AB is 20,BC is 21, find the length of hypotenuse AC and the perimeter of triangle ABC
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Answer:
The length of hypotenuse AC is 29 and the perimeter of triangle ABC is 70 .
Step-by-step explanation:
AB²+ BC² = AC²
(20)² + (21)² = AC²
400 + 441 = AC²
841 = AC²
AC = √841
AC = 29.
perimeter of triangle ABC = sum of three sides
= 20 + 21 +29
= 70
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