Question

If AB is a chord and 'O' is centre of the circle and angle AOB=130° then find
a) angle OAB
b) angle OBA​

Answer 1

Given →

As in the given circle AB is a chord and O is centre . Angle AOB = 130°

To find →

Value of angle OAB and OBA .

Solution →

As by joining OA and OB we got a triangle in which one angle is already given to us and we have to find the remaining two angles .

As OA and OB are the two sides of triangle as well as radius of the given circle so we conclude that OAB is isoceles triangle .

Coz = OA = OB

And we know that Opposite angles of equal sides are also equal .

Angle OAB = OBA

In ∆ OAB let angleOAB as x and AOB as y

by internal angle sum property .

x + x + y = 180° ( Angle A= B )

2x + 130° = 180°

2x. = 50°

x. = 25°

So angle OAB = 25° = OBA

Answer 2

Step-by-step explanation:

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