If AB is a chord of a circle with centre O , AOC is a diameter and AT is a tangent at A , then prove that angle BAT = angle ACB
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simply Write : by alternate segment theorem
and then state the theorem i. e. the angle between the tangent and the chord is equal to the angle formed in the alternate segment
and then state the theorem i. e. the angle between the tangent and the chord is equal to the angle formed in the alternate segment
Aditi1107:
angle BAC + angle BCA = angle TAB + angle BAC = 90degrees. So angle TAB= angle BCA. Proved
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