Question

if AB is a diameter and ∠ADC=124°, then ∠BAC=

Answer 1

☆Answer:

35°

☆explanation:

☞ Given,

In circle with centre O, as AOB is diameter,

==> angle BAC = 90°

[ Angle in a semicircle ]

Now , in cyclic quadrilateral ABCD,

Angle ADC + ABC = 180° [ opposite angles of a cyclic quadrilateral are supplementary ]

==> 124° + angle ABC = 180

==> Angle ABC = 180° - 124°

==> angle ABC = 54°

Thus, in ABC , using Angle Sum Property of angle ,

angle ABC + angle BCA + angle BCA = 180°

==> 54° + 90° + angle BCA = 180°

==> 144° + angle BCA = 180°

==> angle BAC = 180° - 144°

the value of Angle BAC is 34

❥ $\huge\frak\pink{</strong><strong>thnks</strong><strong>!</strong><strong>}$

Answer 2

dint understand the question